URI Online Judge Solution 1073 - Solution in C

Solution in C

#include<stdio.h>

int main()

{

int i,n;

scanf("%d",&n);

if(5<n<2000)

{

for(i=1;i<=n;i++)

{

if(i%2==0)

{

printf("%d^2 = %d\n",i,i*i);

}

}

}

return 0;

}

~~~~~~Happy Coding~~~~~~