URI Online Judge Solution 1036 - Solution in C

Solution in C

#include<stdio.h>

#include<math.h>

int main()

{

    double a,b,c,r1,r2,d;

    scanf("%lf %lf %lf",&a,&b,&c);

    d=(pow(b,2)-(4*a*c));

    r1=(-b+sqrt(d))/(2*a);

    r2=(-b-sqrt(d))/(2*a);

    if(a!=0 && d>0)

       {

          printf("R1 = %.5lf\nR2 = %.5lf\n",r1,r2);

       }

    else{

         printf("Impossivel calcular\n");

       }

      return 0;

}

~~~~~~Happy Coding~~~~~~