URI Online Judge Solution 1037 - Solution in C

Solution in C

#include<stdio.h>

int main()

{

 float n;

 scanf("%f", &n);

 if(n < 0 || n > 100)

 {

printf("Fora de intervalo\n");

 }

 else

 {

  if(n >= 0 && n <= 25)

  {

   printf("Intervalo [0,25]\n");

  }

  else if(n > 25 && n <= 50)

  {

  printf("Intervalo (25,50]\n");

  }

  else if(n > 50 && n <= 75)

  {

  printf("Intervalo (50,75]\n");

  }

  else{

   printf("Intervalo (75,100]\n");

  }

 }

 return 0;

}

~~~~~~Happy Coding~~~~~~